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如何在Excel中生成或列出所有可能的排列?

例如,我有三個字符XYZ,現在,我想基於這三個字符列出所有可能的排列,以獲得六個不同的結果,例如:XYZ,XZY,YXZ,YZX,ZXY和ZYX。 在Excel中,如何根據不同的字符數快速生成或列出所有排列?

根據帶有VBA代碼的字符生成或列出所有可能的排列


箭頭藍色右氣泡 根據帶有VBA代碼的字符生成或列出所有可能的排列

以下VBA代碼可以幫助您根據字母的具體數量列出所有排列,請執行以下操作:

1。 按住 ALT + F11 鍵打開 Microsoft Visual Basic for Applications 窗口。

2。 點擊 插入 > 模塊,然後將以下代碼粘貼到 模塊 窗口。

VBA代碼:列出excel中所有可能的排列

Sub GetString()
'Updateby Extendoffice
    Dim xStr As String
    Dim FRow As Long
    Dim xScreen As Boolean
    xScreen = Application.ScreenUpdating
    Application.ScreenUpdating = False
    xStr = Application.InputBox("Enter text to permute:", "Kutools for Excel", , , , , , 2)
    If Len(xStr) < 2 Then Exit Sub
    If Len(xStr) >= 8 Then
        MsgBox "Too many permutations!", vbInformation, "Kutools for Excel"
        Exit Sub
    Else
        ActiveSheet.Columns(1).Clear
        FRow = 1
        Call GetPermutation("", xStr, FRow)
    End If
    Application.ScreenUpdating = xScreen
End Sub
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
    Dim i As Integer, xLen As Integer
    xLen = Len(Str2)
    If xLen < 2 Then
        Range("A" & xRow) = Str1 & Str2
        xRow = xRow + 1
    Else
        For i = 1 To xLen
            Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
        Next
    End If
End Sub

3。 然後按 F5 鍵以運行此代碼,並彈出一個提示框,提醒您輸入要列出所有排列的字符,請參見屏幕截圖:

文檔列表排列1

4。 輸入字符後,再單擊 OK 按鈕,所有可能的排列都顯示在活動工作表的A列中。 看截圖:

文檔列表排列2

備註:如果輸入的字符長度等於或大於8個字符,則此代碼將無效,因為排列過多。

文檔列表排列3


列出或生成多列中所有可能的組合

如果您需要基於多列數據生成所有可能的組合,也許沒有一種處理任務的好方法。 但, Excel的Kutools's 列出所有組合 實用程序可以幫助您快速輕鬆地列出所有可能的組合。 點擊下載Kutools for Excel!

doc列出所有組合

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Comments (13)
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This comment was minimized by the moderator on the site
Olá !

Como faço para gerar pelo menos 10 permutações ?
This comment was minimized by the moderator on the site
Hello, Mateus,
To solve your problem, please apply the below code:(Note: if there are more than 8 characters, the code will execute slowly.)
Sub GetString()
'Updateby Extendoffice
    Dim xStr As String
    Dim FRow As Long
    Dim FC As Integer
    Dim xScreen As Boolean
    Dim xNumber As Long
    xNumber = 10 ' This is the max length of the characters you can change it to 11, 12, 13...as you need
    xScreen = Application.ScreenUpdating
    Application.ScreenUpdating = False
    xStr = Application.InputBox("Enter text to permute:", "Kutools for Excel", , , , , , 2)
    If Len(xStr) < 2 Then Exit Sub
    If Len(xStr) > xNumber Then
        MsgBox "Too many permutations!", vbInformation, "Kutools for Excel"
        Exit Sub
    Else
        ActiveSheet.Columns(1).Clear
        FRow = 1
        FC = 1
        Call GetPermutation("", xStr, FRow, FC)
    End If
    Application.ScreenUpdating = xScreen
End Sub
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long, ByRef xc As Integer)
    Dim i As Integer, xLen As Integer
    xLen = Len(Str2)
    If xLen < 2 Then
        If xRow > 1000000 Then
            xc = xc + 1
            xRow = 1
        End If
       ActiveSheet.Cells(xRow, xc) = Str1 & Str2
        xRow = xRow + 1
    Else
        For i = 1 To xLen
            Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow, xc)
        Next
    End If
End Sub


Please have a try, hope it can help you!
This comment was minimized by the moderator on the site
Hi there, if the input string contains duplicate chars, then the sub produces duplicate permutations.
This does not happen if you make the following modification the the loop:

' ==========================
For i = 1 To xLen
If Instr( Left(Str2, i - 1), Mid(Str2, i, 1) ) = 0 then
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
End if
Next
' ==========================

Creating temporary local variables for Mid(Str2, i, 1) and for Left(Str2, i - 1), and avoiding the test for i=1 makes it go faster:


' ==========================
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer, Str2left as String, c as String
xLen = Len(Str2)
If xLen < 2 Then
Range("A" & xRow) = Str1 & Str2
xRow = xRow + 1
Else
Call GetPermutation(Str1 + Mid(Str2, 1, 1), Right(Str2, xLen - 1), xRow)
For i = 2 To xLen
c = Mid(Str2, i, 1)
Str2left = Left(Str2, i - 1)
If Instr( Str2left, c ) = 0 then
Call GetPermutation(Str1 + c, Str2left + Right(Str2, xLen - i), xRow)
End If
Next
End If
End Sub
' ==========================

Cheers,
DVdm
This comment was minimized by the moderator on the site
who can send me a list of 10 diferent items permutatted by 2 outcomes. this code doe

snt work on this
This comment was minimized by the moderator on the site
peki bunu listeleyecek bir program uygulama yok mu?basit sıradan bir hesaplamadan daha fazlasına ihtiyacı olan ne yapacak?
This comment was minimized by the moderator on the site
this code will not work because there are two many permutations


should be:

this code will not work because there are too many permutations


HTH
This comment was minimized by the moderator on the site
Hello, MC,
Thank you for your warm reminder, it is my mistake. I have corrected it.
Thanks a lot!
This comment was minimized by the moderator on the site
Hello everyone. I need help on this. I have two alphabets to be permutated in 20 rows. But am not getting it right. Anyone who could help me out should send the permutation to my email. .


1.a b b a
2.a a b b
3.a a b b
4.a a b b
5.a a b b
6.a a b b
7.a a b b
8.a a b b
9.a a b b
10.a a b b
11.a a b b
12.a a b b
13.a a b b
14.a a b b
15.a a b b
16.a a b b
17.a a b b
18.a a b b
19.a a b b
20.a a b b
This comment was minimized by the moderator on the site
How many sequences of 3things can be formed from 7 different things replacement and order is important?
This comment was minimized by the moderator on the site
3 to the power of 7: 2187
This comment was minimized by the moderator on the site
@Supraja...

in the first sub clear all cells... not just the first row
--Cells.Clear

Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer
xLen = Len(Str2)
If xLen < 2 Then
'move to the next column when you get to 100
Cells(((xRow - 1) Mod 100) + 1, 1 + Int(xRow / 100)) = Str1 & Str2
xRow = xRow + 1
Else
For i = 1 To xLen
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
Next
End If
End Sub
This comment was minimized by the moderator on the site
Hello,

Im trying to get a permutation for 82 characters, the code provided works, but, since the columns are only 1048576, I want to move the next output in B,C,D..... Can any of you help me on this regard
This comment was minimized by the moderator on the site
Hello, Im doing a small project using permutation and combination rules. I need your support on this please. Scenario: I have 13 digit alpha numeric data (00SHGO8BJIDG0) I want a coding to interchange S to 5, I to 1 and O to 0 and vise versa. The project is that if I have the correct 13 digit data I will receive a 3 digit pass code. (eg) 00SHG08BJ1DG0 - 500 is the pass code but because of wrong typo that is instead of 1 it was I and 0 it was O there is a wrong info. can you please help me.
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