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如何在Excel中的文本字符串中找到第一個/最後一個數字的位置?

新增一名作者 最後修改時間:2020-07-01

例如,您有一個由字母和數字組成的文本字符串列表。 如果要查找每個字符串中第一個或最後一個數字的位置,該怎麼辦? 實際上,使用公式可以幫助您快速找到指定文本字符串中第一個/最後一個數字的位置。 在本教程中,我們將向您顯示處理此問題的詳細信息。

在Excel中查找文本字符串中第一個數字的位置
在Excel中查找文本字符串中最後一個數字的位置


在Excel中查找文本字符串中第一個數字的位置

如下面的屏幕截圖所示,要在文本字符串中查找第一個數字的位置,請執行以下操作。

1.選擇單元格B2,將以下公式之一複制並粘貼到編輯欄中:

1)。 公式1: = MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&“ 0123456789”));

2)。 公式2: =MATCH(TRUE,ABS(CODE(MID(A2,ROW($A$1:INDEX(A:A,LEN(A2))),1))-52.5)<5,0) + 按Ctrl + 轉移 + Enter;

3)。 公式3: =MIN(IF(ISERROR(FIND({1;2;3;4;5;6;7;8;9;0},A2)),"",FIND({1;2;3;4;5;6;7;8;9;0},A2))).

2.然後,第一個字符串的第一個數字位置顯示在單元格B2中。 現在將“填充手柄”向下拖動到單元格B7,以填充以下範圍。

然後列出整個字符串的所有第一個數字位置。


在Excel中查找文本字符串中最後一個數字的位置

找到第一個數字的位置後,我們現在開始查找字符串中最後一個數字的位置。

在本節中,有兩個公式可供您選擇。

配方1: = MAX(IF(ISNUMBER(VALUE(MID(A2,ROW(INDIRECT(“ 1:”&LEN(A2))),1))),ROW(INDIRECT(“ 1:”&LEN(A2))))) ) + 按Ctrl + 轉移 + Enter;

配方2: =MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0},A2,ROW(INDIRECT("1:"&LEN(A2)))),0)) + 按Ctrl + 轉移 + Enter

1.選擇單元格B2,將以上公式之一複制並粘貼到公式欄中,然後同時按Ctrl + Shift + Enter鍵。 然後您可以看到結果顯示在B2中。

2.選擇B2,將“填充手柄”向下拖動到單元格B7,以自動填充範圍。

然後,您將立即獲得整個文本字符串的所有最後數字的位置。


在一個單元格中輕鬆地將文本和數字從一個單元格分為兩列:

Excel的Kutools 分裂細胞 實用程序中,您可以按特定的分隔符將單元格範圍劃分為行或列,將文本和數字拆分為單元格,也可以通過certian長度拆分文本。 立即下載並嘗試! (30 天免費試用)


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Comments (15)
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This comment was minimized by the moderator on the site
Ich habe gerade diese Lösung ausprobiert und es klappt bei mir nicht. Hat sich inzwischen etwas, was die Matrixformel betrifft, geändert?
This comment was minimized by the moderator on the site
Hi Wolfgang,

The formulas provided in this post work well in my case. What result did you get?
This comment was minimized by the moderator on the site
Thought I would let everyone know that I needed to find the last position of the house numbers in an address field in access. The only way I could do this was to export a short query to excel and run this formula. I know there is a way to get the excel functions in access but this was much easier. I had addresses that had varying house number lengths and then you throw in the 1st, 2nd, 3rd...St., Ave into the mix within the street name and you got a major problem parsing a very bad formatted address string.

address examples 1234 nw (or NW) 4th St.
12 West St North (or N)
123,456, and 789 Heritage Circle (or Crc)
123 & 456 N 1st. St

I figured out a way to parse off the first and second example real quick with some research (I would give credit, but right now I can't remember where I got the answer). It involved creating a VBA function to accomplish it. That worked great but I came to a problem when we come to the first "," or "and" or "&".

Using this formula in excel found the last number I needed without choosing the street number. Since most house numbers ended with a space " " between them and the direction segment or the street name segment, I added --- &" " after the find formula. Like this: in an array formula
=MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0}&" ",E2,ROW(INDIRECT("1:"&LEN(E2)))),0))
A quick export back to an access table and wala! you have the number.
202 & 206 N Blanche Ave = 9

Now I know I could probably parse the rest of the address in excel but it actually worked real well in Access, so I just decided to do the rest there.

If there is a way to do it all in Access, I couldn't find it or figure it out.
This comment was minimized by the moderator on the site
goood, thanks
This comment was minimized by the moderator on the site
That's what I needed =MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789"));

thank you very much!
This comment was minimized by the moderator on the site
You are welcome O(∩_∩)O
This comment was minimized by the moderator on the site
how to get this to work in powerpivot
This comment was minimized by the moderator on the site
Hi,
Sorry can't help with this.
This comment was minimized by the moderator on the site
.... and here I thought that I knew Excel well. Bravo!!!!!
This comment was minimized by the moderator on the site
And here is a formula for finding the position of the last numeric character in a string, but WITHOUT using an array formula: =MAX(SEARCH(CHAR(9),SUBSTITUTE("0123456789"&A1,{0,1,2,3,4,5,6,7,8,9},CHAR(9),LEN(A1)+10-LEN(SUBSTITUTE("0123456789"&A1,{0,1,2,3,4,5,6,7,8,9},"")))))-10 The number 10 appearing in this formula, are due to the length of the constant string "0123456789", that is concatenated in this formula.
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Many Thanks , Great
This comment was minimized by the moderator on the site
Hi George, your formula is may meet my requirement. I need similar formula to find out digit position in the string listed in "A" row in B row Required output 8 5 1 4 3 1 3 2 5 5 6 6 1 7 9 9 1 1 6 0 9 3 0 2 7 4 9 3 6 5 5 7 4 9 8 10 2 10 0 8 1 9
This comment was minimized by the moderator on the site
This was exactly what I wanted. Thank you.
This comment was minimized by the moderator on the site
The function 1). Formula 1: =MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789")); It's absolutely what i needed and extremely cool! Thanks so much! Jon
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Hats off mate..
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